A) Pressure of the gas increases
B) The rate of collision increases
C) The number of moles of gas increases
D) The energy of gaseous molecules increases
Correct Answer: C
Solution :
At constant V of a definite mass \[\frac{{{P}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}}\therefore \frac{{{P}_{1}}}{{{P}_{2}}}=\frac{300}{600}=\frac{1}{2}\] i.e. pressure increases and on increasing temperature energy of molecules increases so the rate of collisions also increases and number of moles remains constant because there is neither addition nor removal of gas in the occurring.
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