JEE Main & Advanced Chemistry States of Matter Question Bank Ideal gas equation and Related gas laws

  • question_answer 400 \[c{{m}^{3}}\] of oxygen at\[{{27}^{o}}C\]were cooled to \[-{{3}^{o}}C\] without change in pressure. The contraction in volume will be

    A)                 40 \[c{{m}^{3}}\]             

    B)                 30 \[c{{m}^{3}}\]

    C)                 44.4 \[c{{m}^{3}}\]         

    D)                 360 \[c{{m}^{3}}\]

    Correct Answer: A

    Solution :

               \[{{V}_{2}}=\frac{{{T}_{2}}}{{{T}_{1}}}.{{V}_{1}}=\frac{{{270}^{o}}K}{{{300}^{o}}K}.400c{{m}^{3}}=360c{{m}^{3}}\]                                 contraction \[={{V}_{1}}-{{V}_{2}}=400-360=40c{{m}^{3}}\]


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