A) 0.4 litres
B) 0.8 litres
C) 27.8 litres
D) 55.6 litres
Correct Answer: A
Solution :
\[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\because {{V}_{2}}=\frac{{{T}_{2}}}{{{T}_{1}}}{{V}_{1}}\] \[=\frac{{{546}^{o}}K}{{{273}^{o}}K}\times 0.2L=0.4L.\]
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