JEE Main & Advanced Chemistry States of Matter Question Bank Ideal gas equation and Related gas laws

  • question_answer The pressure and temperature of \[4d{{m}^{3}}\] of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be     [KCET 2004]

    A)                 \[2\,d{{m}^{3}}\]            

    B)                 \[3d{{m}^{3}}\]

    C)                 \[4\,d{{m}^{3}}\]            

    D)                 \[8\,d{{m}^{3}}\]

    Correct Answer: C

    Solution :

               \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\]; \[\frac{{{P}_{1}}\times 4}{{{T}_{1}}}=\frac{2{{P}_{1}}\times {{V}_{2}}}{2{{T}_{1}}}\]                                 \[8=2\times {{V}_{2}}\] so \[{{V}_{2}}=4d{{m}^{3}}\]

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