A) \[1\times {{10}^{-6}}\]
B) \[1\times {{10}^{-9}}\]
C) \[1\times {{10}^{-12}}\]
D) \[{{K}_{SP}}\]
Correct Answer: C
Solution :
\[{{K}_{w}}=[{{H}_{3}}{{O}^{+}}]\,\,[O{{H}^{-}}]\] Concentration of \[{{H}_{3}}{{O}^{+}}\]in distilled water \[=1\times {{10}^{-6}}\]mol/l. Now \[[{{H}_{3}}{{O}^{+}}]=[O{{H}^{-}}]\] \[{{K}_{w}}=[1\times {{10}^{-6}}]\times [1\times {{10}^{-6}}]=1\times {{10}^{-12}}\].
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