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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Hydrogenion concentration pH scale and buffer solution

  • question_answer
    The \[pH\] of a simple sodium acetate buffer is given by \[pH=p{{K}_{a}}+\log \frac{[Salt]}{[Acid]}\]                 \[{{K}_{a}}\]of acetic acid \[=1.8\times {{10}^{-5}}\] If [Salt] = [Acid] = 0.1 M, the \[pH\]of the solution would be about           [BHU 1987]

    A)                 7             

    B)                 4.7

    C)                 5.3         

    D)                 1.4

    Correct Answer: B

    Solution :

               [Salt]= 0.1 M, [Acid]= 0.1 M                    \[{{K}_{a}}=1.8\times {{10}^{-5}}\] ;  \[pH=-\log {{K}_{a}}+\text{log}\frac{\text{ }\!\![\!\!\text{ Salt }\!\!]\!\!\text{ }}{\text{ }\!\![\!\!\text{ Acid }\!\!]\!\!\text{ }}\]            \[=-\text{log}1.8\times {{10}^{-5}}+\text{log}\frac{0.1}{0.1}\]\[=-\text{log}\,\,1.8\times {{10}^{-5}}\]                                 \[pH=4.7\].


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