A) \[0.01\,M\,\,KOH\]
B) \[1\,N\,\,KOH\,\,ml\]
C) \[1\,N\,NaOH\,\,ml\]
D) \[3.0\times {{10}^{-7}}\,M\]
Correct Answer: A
Solution :
\[[O{{H}^{-}}]={{10}^{-2}}\]M ; \[pOH=2\] \[pH+pOH=14\];\[pH=14-pOH\] \[pH=14-2=12\]
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