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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Hydrogenion concentration pH scale and buffer solution

  • question_answer
    What will be the \[pH\] of a solution formed by mixing \[40\,\,ml\] of \[0.10\,\,M\,\,HCl\] with \[10\,\,ml\] of \[0.45\,\,M\,\,NaOH\] [Manipal MEE 1995]

    A)                 12          

    B)                 10

    C)                 8             

    D)                 6

    Correct Answer: A

    Solution :

               M.eq. of 0.10 \[M\,\,HCl=\frac{0.10}{1000}\times 40=0.004M\]                    M.eq. of 0.45 \[M\,\,NaOH=\frac{0.45\times 10}{1000}=0.0045M\]                    Now left \[[O{{H}^{-}}]=0.0045-0.004\]\[=5\times {{10}^{-4}}\]M                    Total volume = 50 ml.                    \[[O{{H}^{-}}]=\frac{5\times {{10}^{-4}}}{50}\times 1000\]; \[[O{{H}^{-}}]=1\times {{10}^{-2}}\]                                 pOH = 2 ;  pH = 14 ? pOH = 12.


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