A) \[{{10}^{-12}}\]
B) \[{{10}^{-14}}\]
C) \[{{10}^{-16}}\]
D) \[{{10}^{-10}}\]
Correct Answer: A
Solution :
Ka of \[{{H}_{2}}{{O}_{2}}=1.55\times {{10}^{-12}}\]
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