A) Green
B) Red
C) Blue
D) Black
Correct Answer: C
Solution :
This is due to the formation of \[Cr{{O}_{5}}\]. \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}+4{{H}_{2}}{{O}_{2}}\to {{K}_{2}}S{{O}_{4}}+\underset{\text{Blue}}{\mathop{2Cr{{O}_{5}}}}\,+5{{H}_{2}}O\]
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