• # question_answer 1 ml of ${{H}_{2}}{{O}_{2}}$ solution gives 10 ml of ${{O}_{2}}$ at NTP. It is A) 10 vol. ${{H}_{2}}{{O}_{2}}$ B) 20 vol. ${{H}_{2}}{{O}_{2}}$ C) 30 vol. ${{H}_{2}}{{O}_{2}}$ D) 40 vol. ${{H}_{2}}{{O}_{2}}$

10 volume of ${{H}_{2}}{{O}_{2}}$ means 10 ml of ${{O}_{2}}$ is obtained from 1 ml of ${{H}_{2}}{{O}_{2}}$.