• # question_answer 20 volume ${{H}_{2}}{{O}_{2}}$ solution has a strength of about A) 30% B) 6% C) 3% D) 10%

$\because$ 22.4 litre ${{O}_{2}}$ at N.T.P. obtained by 68 gm of ${{H}_{2}}{{O}_{2}}$ \ 1 litre ${{O}_{2}}$at N.T.P. obtained by$\frac{68}{22.4}$gm of ${{H}_{2}}{{O}_{2}}$ \ 20 litre ${{O}_{2}}$ at N.T.P. obtained by $\frac{68}{22.4}\times 20$gm of ${{H}_{2}}{{O}_{2}}=60.71\,gm$ of ${{H}_{2}}{{O}_{2}}$ \ 1000 ml ${{O}_{2}}$ at N.T.P. obtained by = 60.71 gm of ${{H}_{2}}{{O}_{2}}$ \ 100 ml ${{O}_{2}}$ at N.T.P. obtained by $=\frac{60.71}{1000}\times 100=6.71%$