A) \[Pb{{O}_{2}}(s)+{{H}_{2}}{{O}_{2}}(aq)\to PbO(s)+{{H}_{2}}O(l)+{{O}_{2}}(g)\]
B) \[N{{a}_{2}}S{{O}_{3}}(aq)+{{H}_{2}}{{O}_{2}}(aq)\to N{{a}_{2}}S{{O}_{4}}(aq)+{{H}_{2}}O(l)\]
C) \[2Kl(aq)+{{H}_{2}}{{O}_{2}}(aq)\to 2KOH(aq)+{{I}_{2}}(s)\]
D) \[KN{{O}_{2}}(aq)+{{H}_{2}}{{O}_{2}}(aq)\to KN{{O}_{3}}(aq)+{{H}_{2}}O(l)\]
Correct Answer: A
Solution :
In the following reaction \[{{H}_{2}}{{O}_{2}}\] acts as a reducing agent. \[Pb{{O}_{2}}(s)+{{H}_{2}}{{O}_{2}}(aq)\to PbO(s)+{{H}_{2}}O(l)+{{O}_{2}}(g)\]
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