A) \[s{{p}^{3}}\]
B) \[s{{p}^{2}}\]
C) \[ds{{p}^{3}}\]
D) \[{{d}^{2}}s{{p}^{3}}\]
Correct Answer: A
Solution :
\[P{{F}_{3}}\] consist of three bonding pair electrons and one lone pair of electron hence it shows \[s{{p}^{3}}\]? hybridization.
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