A) \[\frac{1}{4}s-\]character
B) \[\frac{1}{2}s-\]character
C) \[\frac{2}{3}s-\]character
D) \[\frac{3}{4}s-\]character
Correct Answer: A
Solution :
In \[s{{p}^{3}}\]?hybridisation each \[s{{p}^{3}}\]hybridised orbital has 1/4 s-character.
You need to login to perform this action.
You will be redirected in
3 sec
