question_answer

The structural formula of a compound is \[C{{H}_{3}}-CH=C=C{{H}_{2}}.\] The type of hybridization at the four carbons from left to right are                  [CBSE PMT 1989]

A)                 \[s{{p}^{2}},\,\,sp,\,\,s{{p}^{2}},\,\,s{{p}^{3}}\]

B)                 \[s{{p}^{2}},\,\,s{{p}^{3}},\,\,s{{p}^{2}},\,\,sp\]

C)                 \[s{{p}^{3}},\,\,s{{p}^{2}},\,\,sp,\,\,s{{p}^{2}}\]

D)                 \[s{{p}^{3}},\,\,s{{p}^{2}},\,\,s{{p}^{2}},\,\,s{{p}^{2}}\]