A) Only \[sp\]hybridized carbon atoms
B) Only \[s{{p}^{2}}\]hybridized carbon atoms
C) Both \[sp\]and \[s{{p}^{2}}\]hybridized carbon atoms
D) \[sp,\,\,s{{p}^{2}}\] and \[s{{p}^{3}}\]hybridized carbon atoms
Correct Answer: D
Solution :
\[\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{sp}{\mathop{C}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,\overset{s{{p}^{3}}\,\,}{\mathop{C{{H}_{3}}}}\,\] 1, 2-butadiene.
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