A) \[Ca{{I}_{2}}\]
B) \[C.C{{l}_{2}}=C.C{{l}_{2}}\]
C) \[C{{H}_{2}}=C=C{{H}_{2}}\]
D) \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
Correct Answer: C
Solution :
In compound \[\overset{3}{\mathop{C}}\,{{H}_{2}}=\overset{2}{\mathop{C}}\,=\overset{1}{\mathop{C}}\,{{H}_{2}}\] the second carbon sp-hybridised.
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