question_answer

 The hybrdization of \[I{{F}_{7}}\] is         [Pb. CET 2001]

A)                 \[s{{p}^{3}}{{d}^{3}}\]  

B)                 \[s{{p}^{2}}d\]

C)                 \[{{d}^{2}}s{{p}^{3}}\]  

D)                 \[s{{p}^{3}}\]

Correct Answer: A

Solution :

           The electronic configuration of                    \[I=[Xe]\ 5{{s}^{2}},5{{p}^{5}}\] hence IF7 shows \[s{{p}^{3}}{{d}^{2}}\]hybridization. So, its structure is pentagonal bipyramidal.