A) \[sp\]
B) \[s{{p}^{2}}\]
C) \[s{{p}^{3}}\]
D) \[s{{p}^{3}}d\]
Correct Answer: B
Solution :
In the formation of \[B{{F}_{3}}\] molecule, one s and 2p orbital hybridise. Therefore it is \[s{{p}^{2}}\] hybridization.
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