question_answer

Hybridization of Fe in \[{{K}_{3}}Fe{{(CN)}_{6}}\] is [DCE 2002]

A) \[s{{p}^{3}}\]

B) \[ds{{p}^{3}}\]

C) \[s{{p}^{3}}{{d}^{2}}\]

D) \[{{d}^{2}}s{{p}^{3}}\]

Correct Answer: D

Solution :

\[{{K}_{3}}[Fe{{(CN)}_{6}}]\] Electronic configuration of \[Fe=[Ar]4{{s}^{2}}3{{d}^{6}}\] Electronic configuration of \[F{{e}^{+3}}=[Ar]3{{d}^{5}}\] Number of ligand (coordination numbr)=6 Nature of ligand is strong field. Hybridization of \[Fe\] is \[{{d}^{2}}s{{p}^{3}}\].