A) 8
B) 6
C) 7
D) 9
Correct Answer: A
Solution :
Here we have perimeter of the triangle = 32 cm Let a = 8 cm and b = 11 cm Third side, \[c=32-(8+11)=13\,cm\] \[\therefore \] \[s=\frac{32}{2}=16\,cm\] Therefore, area of the triangle \[=\sqrt{s(s-a)(s-b)(s-c)}\] \[=\sqrt{16\times 8\times 5\times 3}\,c{{m}^{2}}\] \[=80\sqrt{30}\,c{{m}^{2}}=k\sqrt{30}\,c{{m}^{2}}\] \[\therefore \]\[k\sqrt{30}=8\sqrt{30}\Rightarrow k=8\]
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