A) \[13.24\,c{{m}^{2}}\]
B) \[~12.28\,c{{m}^{2}}\]
C) \[~11.32\,c{{m}^{2}}\]
D) \[~15.37\,c{{m}^{2}}\]
Correct Answer: B
Solution :
Here a = 1 cm, b = 4 cm, c = 8 cm \[\therefore \] \[s=\frac{11+4+8}{2}=\frac{23}{2}=11.5\,cm\] Area \[=\sqrt{11.5\times (11.5-11)\times (11.5-4)\times (11.5-8)}\] \[=\sqrt{11.5\times 0.5\times 7.5\times 3.5}\] \[=\sqrt{150.94}=12.8\,c{{m}^{2}}\]
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