A) \[-\,212{}^\circ C\]
B) \[-\,40{}^\circ C\]
C) \[-\,32{}^\circ C\]
D) \[32{}^\circ C\]
Correct Answer: B
Solution :
\[\frac{C}{5}=\frac{F-32}{9}\,\,Here\,\,C=F\] \[\frac{C}{5}=\frac{F-32}{9}\Rightarrow 9C=5C-160\]\[4C=-160\Rightarrow C=-{{40}^{o}}C\] Thus at \[-\,40{}^\circ C\] and \[-\,40{}^\circ F\] the temperature is same.
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