A) \[50{}^\circ C\]
B) \[100{}^\circ C\]
C) \[80{}^\circ C\]
D) \[150{}^\circ C\]
Correct Answer: B
Solution :
Heat required by ice to raise its temperature to \[100{}^\circ C,\] \[\begin{align} & {{Q}_{1}}={{m}_{1}}{{L}_{1}}+{{m}_{1}}{{c}_{1}}{{\theta }_{1}}=5\times 80+5\times 1\times 100 \\ & =400+500=900cal \\ \end{align}\] Heat given by steam when condensed, \[\begin{align} & {{Q}_{2}}={{m}_{2}}{{L}_{2}}=5\times 536=2680cal \\ & {{Q}_{2}}>{{Q}_{1}} \\ \end{align}\] This means that whole steam is not even condensed. Hence temperature of mixture will remain at \[100{}^\circ C\].
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