A) \[\frac{a}{\sqrt{1-{{a}^{2}}{{b}^{2}}}}\]
B) \[\frac{a}{1-{{a}^{2}}{{b}^{2}}}\]
C) \[a\]
D) \[\frac{1}{1-{{a}^{2}}{{b}^{2}}}\]
Correct Answer: C
Solution :
\[H.M.=\frac{2\left( \frac{{{a}^{2}}}{1-{{a}^{2}}{{b}^{2}}} \right)}{\frac{a}{1-ab}+\frac{a}{1+ab}}=\frac{2{{a}^{2}}}{2a}=a\].
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