JEE Main & Advanced Mathematics Sequence & Series Question Bank Harmonic Progression

  • question_answer
    H.M. between the roots of the equation \[{{x}^{2}}-10x+11=0\] is [MP PET 1995]

    A) \[\frac{1}{5}\]

    B) \[\frac{5}{21}\]

    C) \[\frac{21}{20}\]

    D) \[\frac{11}{5}\]

    Correct Answer: D

    Solution :

    Let roots be \[\alpha ,\ \beta \] then H.M. \[=\frac{2\alpha \beta }{\alpha +\beta }=\frac{11\times 2}{10}=\frac{11}{5}\].


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