A) 16
B) 14
C) \[\frac{27}{14}\]
D) \[\frac{56}{15}\]
Correct Answer: D
Solution :
Obviously, \[{{7}^{th}}\] term of corresponding A.P. is \[\frac{1}{8}\] and \[{{8}^{th}}\] term will be\[\frac{1}{7}\]. \[a+6d=\frac{1}{8}\] and\[a+7d=\frac{1}{7}\] Solving these, we get \[d=\frac{1}{56}\] and \[a=\frac{1}{56}\] Therefore \[{{15}^{th}}\] term of this A.P. \[=\frac{1}{56}+14\times \frac{1}{56}=\frac{15}{56}\] Hence the required \[{{15}^{th}}\] term of the H.P. is\[\frac{56}{15}\].
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