• # question_answer Concentrated $HN{{O}_{3}}$ reacts with ${{I}_{2}}$ to give [IIT 1989; Roorkee 1995; JIPMER 2001] A) $HI$ B) $HOI$ C) $HOI{{O}_{3}}$ D) $HOI{{O}_{3}}$

${{I}_{2}}+10HN{{O}_{3}}\,\to \,2HI{{O}_{3}}+10N{{O}_{2}}+4{{H}_{2}}O$