JEE Main & Advanced Chemistry The p-block Elements-II / p-ब्लॉक तत्व-II Question Bank Halogen Family

  • question_answer
    \[HI\] cannot be prepared by the action of conc. \[{{H}_{2}}S{{O}_{4}}\] on \[KI\] because [MNR 1984]

    A) \[HI\] is stronger than \[{{H}_{2}}S{{O}_{4}}\]

    B) \[HI\] is more volatile than \[{{H}_{2}}S{{O}_{4}}\]

    C) \[{{H}_{2}}S{{O}_{4}}\] is an oxidising agent

    D) \[{{H}_{2}}S{{O}_{4}}\] forms complex

    Correct Answer: C

    Solution :

    \[KI+{{H}_{2}}S{{O}_{4}}\,\to \,KHS{{O}_{4}}+HI\] HI is formed but it is further oxidised by conc. \[{{H}_{2}}S{{O}_{4}}\] into \[{{I}_{2}}\] \[2HI+{{H}_{2}}S{{O}_{4}}\,\to \,2{{H}_{2}}O+\underset{\text{Violet vapour}}{\mathop{{{I}_{2}}+S{{O}_{2}}}}\,\uparrow \]

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