• # question_answer When chlorine water is exposed to sunlight, ${{O}_{2}}$ is liberated. Hence [AFMC 1989] A) Hydrogen has little affinity to ${{O}_{2}}$ B) Hydrogen has more affinity to ${{O}_{2}}$ C) Hydrogen has more affinity to $C{{l}_{2}}$ D) It is a reducing agent

Solution :

$\underset{\text{Exposed to air}}{\mathop{{{H}_{2}}O+C{{l}_{2}}}}\,\,\to \,HCl+HClO$ $HClO\,\to \,HCl+[O]$ or $2HClO\,\to \,2HCl+{{O}_{2}}$

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