• # question_answer The electrolysis of a certain liquid resulted in the formation of hydrogen at the cathode and chlorine at the anode. The liquid is [EAMCET 1979] A) Pure water B) ${{H}_{2}}S{{O}_{4}}$ solution C) $NaCl$solution in water D) $CuC{{l}_{2}}$ solution in water

Solution :

$2NaCl+2{{H}_{2}}O\,\,\to \,\,2NaOH+\underset{\text{(anode)}}{\mathop{C{{l}_{2}}}}\,+\underset{\text{(cathode)}}{\mathop{{{H}_{2}}}}\,$

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