A) \[F\]
B) \[Cl\]
C) \[Br\]
D) \[I\]
Correct Answer: A
Solution :
\[{{F}_{2}}+2C{{l}^{-}}\,\to \,C{{l}_{2}}+2{{F}^{-}}\] \[{{F}_{2}}+2B{{r}^{-}}\,\to \,B{{r}_{2}}+2{{F}^{-}}\] \[{{F}_{2}}+2{{I}^{-}}\,\to \,{{I}_{2}}+2{{F}^{-}}\]
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