A) \[Br\] from \[NaBr\] solution
B) \[F\] from \[NaF\] solution
C) \[Cl\] from \[NaCl\] solution
D) \[F\] from \[Ca{{F}_{2}}\] solution
Correct Answer: A
Solution :
\[C{{l}_{2}}+2NaBr\,\to \,2NaCl+B{{r}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
