• # question_answer A quick supply of $C{{l}_{2}}$ gas may be made by reacting crystals of $KMn{{O}_{4}}$ with a concentrated solution of [CPMT 1973] A) Potassium chloride B) Sodium chloride C) Bleaching powder D) Hydrochloric acid

$2KMn{{O}_{4}}+16HCl\,\to$$2KCl+2MnC{{l}_{2}}+5C{{l}_{2}}+8{{H}_{2}}O$