A) \[C{{O}_{2}}\]
B) \[S{{O}_{2}}\]
C) \[Cl{{O}_{2}}\]
D) \[Si{{O}_{2}}\]
Correct Answer: C
Solution :
Due to unpaired \[{{e}^{-}}\]\[Cl{{O}_{2}}\] is paramagnetic.
You need to login to perform this action.
You will be redirected in
3 sec
