A) \[NaF\] and \[O{{F}_{2}}\]
B) \[NaF+{{O}_{3}}\]
C) \[{{O}_{2}}\ \text{and}\ {{O}_{3}}\]
D) \[NaF+{{O}_{2}}\]
Correct Answer: A
Solution :
Fluorine is the most electronegative element. It does not form oxyfluoxides like other halogens. If reacts with NaOH to form sodium fluoride and oxygen fluoride. \[2NaOH+2{{F}_{2}}\to 2NaF+O{{F}_{2}}+{{H}_{2}}O\]
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