• # question_answer On heating $KCl{{O}_{3}}$, we get [CPMT 1999] A) $C{{l}_{2}}O$ B) $Cl{{O}_{2}}$ C) $Cl{{O}_{3}}$ D) $C{{l}_{2}}{{O}_{7}}$

$3KCl{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\,\xrightarrow{\text{Heat}}\,$$3KHS{{O}_{4}}+HCl{{O}_{4}}+2Cl{{O}_{2}}+{{H}_{2}}O$