• question_answer $C{{l}_{2}}$ reacts with $C{{S}_{2}}$ in presence of ${{I}_{2}}$ catalyst to form [AFMC 1995] A) $CHC{{l}_{3}}$ B) $CC{{l}_{4}}$ C) ${{C}_{2}}{{H}_{5}}Cl$ D) ${{C}_{2}}{{H}_{6}}$

$C{{S}_{2}}+3C{{l}_{2}}\,\xrightarrow{{{I}_{2}}}\,CC{{l}_{4}}+{{S}_{2}}C{{l}_{2}}$