A) \[NaCl\] and \[Mn{{O}_{2}}\]
B) \[NaCl\] and \[HN{{O}_{3}}\](conc.)
C) \[NaCl\] and \[{{H}_{2}}S{{O}_{4}}\] (conc.)
D) \[HCl\] (conc.) and \[KMn{{O}_{4}}\]
Correct Answer: D
Solution :
\[2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}+10HCl\,\to \]\[{{K}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}+8{{H}_{2}}O+5C{{l}_{2}}\]
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