• # question_answer When $C{{l}_{2}}$ gas is passed through hot and conc. solution of $KOH$, following compound is formed [CPMT 1971, 79; BVP 2003] A) $KCl$ B) $KCl{{O}_{3}}$ C) $KCl{{O}_{2}}$ D) $KCl{{O}_{4}}$

Solution :

$6KOH+3C{{l}_{2}}\,\to \,5KCl+KCl{{O}_{3}}+3{{H}_{2}}O$.

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