A) \[2KI+B{{r}_{2}}\to 2KBr+{{I}_{2}}\]
B) \[2{{H}_{2}}O+2{{F}_{2}}\to 2HF+{{O}_{2}}\]
C) \[2KBr+{{I}_{2}}\to 2KI+B{{r}_{2}}\]
D) \[2KBr+C{{l}_{2}}\to 2KCl+B{{r}_{2}}\]
Correct Answer: C
Solution :
\[2KBr+{{I}_{2}}\to 2KI+B{{r}_{2}}\] Iodine is a less electronegative compare to Bromine hence iodine does not change \[B{{r}^{-}}\]to \[B{{r}_{2}}\].
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