A) \[KMn{{O}_{4}}+NaCl\]
B) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+Mn{{O}_{2}}\]
C) \[P{{b}_{2}}{{(N{{O}_{3}})}_{4}}+Mn{{O}_{2}}\]
D) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+HCl\]
Correct Answer: D
Solution :
\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+14HCl\,\,\to \,\,2KCl+2CrC{{l}_{3}}\]\[+7{{H}_{2}}O+3C{{l}_{2}}\]
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