A) \[{{(CN)}_{2}}\]
B) Addition compound \[HgC{{l}_{2}}.\,Hg{{(CN)}_{2}}\]
C) \[Hg(CN)\,Cl\]
D) \[Hg\,[Hg{{(CN)}_{2}}C{{l}_{2}}]\]
Correct Answer: A
Solution :
\[\underset{\text{Mercuric}\,\,\text{chloride}}{\mathop{HgC{{l}_{2}}}}\,+\underset{\text{Mercuric}\,\,\text{cyanide}}{\mathop{Hg\,{{(CN)}_{2}}}}\,\to HgC{{l}_{2}}\,.\,Hg\,{{(CN)}_{2}}\]
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