A) \[C{{l}_{2}}O\]
B) \[Cl{{O}_{2}}\]
C) \[C{{l}_{2}}{{O}_{6}}\]
D) \[C{{l}_{2}}{{O}_{7}}\]
Correct Answer: D
Solution :
\[2HCl{{O}_{4}}\,\to \,{{H}_{2}}O+C{{l}_{2}}{{O}_{7}}\].
You need to login to perform this action.
You will be redirected in
3 sec
