question_answer

If the diameter of the earth becomes twice its present value but its mass remains unchanged, then how would be the weight of an object on the surface of the earth affected?                             

Answer:

                Weight of body, \[W=mg=\frac{GMm}{{{R}^{2}}}\] When the diameter or radius of the earth becomes double its present value, the weight of the body will be \[W'=\frac{GMm}{{{(2R)}^{2}}}=\frac{1}{4}W\] i.e., weight will become one-fourth of the present value.