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JEE Main & Advanced Physics Wave Mechanics Question Bank Graphical Questions

  • question_answer
    Fig. below shows the wave \[y=A\sin (\omega t-kx)\] at any instant travelling in the +ve x-direction. What is the slope of the curve at B                            

    A)            \[\omega /A\]

    B)            \[k/A\]

    C)            \[kA\]

    D)            \[\omega A\]

    Correct Answer: C

    Solution :

                       The particle velocity is maximum at B and is given by \[\frac{dy}{dt}={{({{v}_{p}})}_{\max }}=\omega A\] Also wave velocity is \[\frac{dx}{dt}=v=\frac{\omega }{k}\] So slope \[\frac{dy}{dx}=\frac{{{({{v}_{p}})}_{\max }}}{v}=kA\]


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