A) 1 ´102 N/m
B) 150 N/m
C) 0.667 ´ 102 N/m
D) 3 ´ 102 N/m
Correct Answer: B
Solution :
Total potential energy = 0.04 J Resting potential energy =0.01 J Maximum kinetic energy =(0.04?0.01) \[=0.03J=\frac{1}{2}m\ {{\omega }^{2}}{{a}^{2}}=\frac{1}{2}k{{a}^{2}}\] \[0.03=\frac{1}{2}\times k\times {{\left( \frac{20}{1000} \right)}^{2}}\] \[k=0.06\times 2500\ N/m=150\ N/m\].
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