A) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\to 2{{C}_{3}}{{H}_{4}}{{O}_{3}}+4H\]
B) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}+6C{{O}_{2}}\to 6C{{O}_{2}}+6{{H}_{2}}O\]
C) \[6{{H}_{2}}O+6C{{O}_{2}}\to {{C}_{6}}{{H}_{12}}{{O}_{6}}+6C{{O}_{2}}\]
D) None of these
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]is glucose and \[{{C}_{3}}{{H}_{4}}{{O}_{3}}\]is pyruvic acid.
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