A) \[90{}^\circ \]
B) \[30{}^\circ \]
C) \[40{}^\circ \]
D) \[60{}^\circ \]
Correct Answer: A
Solution :
\[2\angle A=3\angle B=6\angle C=x{}^\circ \] \[\angle A=\frac{x{}^\circ }{2}\] \[\angle B=\frac{x{}^\circ }{3}\] \[\angle C=\frac{x{}^\circ }{6}\] We know that \[\angle A+\angle B+\angle C=180{}^\circ \] \[\frac{x{}^\circ }{2}+\frac{x{}^\circ }{3}+\frac{x{}^\circ }{6}=180{}^\circ \] \[\frac{3x+2x+x}{6}=180{}^\circ \] \[\frac{6x}{6}=180{}^\circ \] \[x=180{}^\circ ,\angle A=\frac{180{}^\circ }{2}=90{}^\circ \]
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